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I can show you how to do calculations like 1/3+1/6, 23*46 or 1331:11.

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id: 1534

10+?=20

id: 5072

$5\cdot \frac{2}{5}=\frac{?}{5}$

id: 10156

Why does the equation (x-5)(x-4)=0 have exactly the two solutions 4 and 5.

  • You can see that $(x-5)(x-4)=0$ for $x=4$ and $x=5$, but there might be other solutions.
    Just put $x=4$ and $x=5$ into the equation and calculate.
    Because $0\cdot 1=0$ and $-1\cdot 0=0$.
    A product of two factors is exactly zero if one of the factors is zero. So (x-5)(x-4)=0 if and only if either (x-5)=0 or (x-4)=0. (x-5)=0 has the solution x=5 and (x-4)=0 has the solution x=4.