We are given an equilateral triangle with side lengths 1. Lets denote the height of that triangle by $h.$ The height divides the triangle into two congruent right triangles with angles $30^{\circ}$ and $60^{\circ}$, hypotenuse 1 and side lengths 0.5 and $h.$ This implies $\sin 60^{\circ}=\cos 30^{\circ}=\frac{h}{1}=h.$ What is the height of the equilateral triangle $h?$